Daily Coding Problem 6MAY2020

I am subscribed to dailycodingproblem.com. From time to time I will share problems I attempt and have a discussion around it. My solution might have bugs or might not be the most efficient but it would be my attempt. Feel free to criticise.

Today's problem I got

This problem was recently asked by Google.

Given a list of numbers and a number k, return whether any two numbers from the list add up to k.

For example, given [10, 15, 3, 7] and k of 17, return true since 10 + 7 is 17.

Bonus: Can you do this in one pass?

This was my solution in javascript. I am using the Javascript for Android app

var map = {10:1,15:1,3:1,7:1};
var k=17;
var result=false;

for (m in map) {
if (map[k-m] == 1) result=true;


I used a hash table (problem did not specify that an array had to be used) where the values were the keys and made one pass, looking for the difference. I would say the time complexity of this solution is O(n).


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